Question

an fcc lattice has a lattice parameter a=300pm calculate the molar volume​

Answer 1

HELLO THERE!

This is really simple. The lattice is Face centered cubic, and the edge length is given. The molar volume is calculated by:

$V = a^{3}$

Here, let's convert the unit of edge length from picometre to metre.

$1 pm = 10^{-12} m\\300 pm = 300 \times 10^{-12} m\\= 3\times 10^{-10} m$

Now,

$V = (3)^{3} \times 10^{-30} m^{3}\\= 27 \times 10^{-30}\\= 2.7 \times 10^{-29}$

Thanks!

Answer 2

Answer:

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