An FCC lattice has lattice parameter of a=400 pm. calculate molar volume of the lattice including all the empty spaces?
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Given:
Lattice parameter, a = 400 pm = 400 × 10⁻¹⁰ cm
The Lattice is Face Centred Cubic.
To Find:
Molar volume of the lattice.
Calculation:
Volume of 1 unit cell = a³
⇒ V = (400 × 10⁻¹⁰)³
⇒ V = 64 × 10⁻²⁴ cm³
- Volume of 1 mole of unit cells = × V
⇒ V' = 6.022 × 10²³ × 64 × 10⁻²⁴
⇒ V' = 38.541 cm³
- Molar Volume = 38.54/4 = 9.64 cm³ (or mL)
- Hence, molar volume of the given lattice is 9.64 cm³ (or 9.64 mL).
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