Question

an И
Find
arithmetic sequence 37, 74, 111, 148,
explicit formula for the​

Answer 1

Answer:

a, a+d, a+2d, a+3d...

Step-by-step explanation:

$0 + 37 = 37 \\ 37 + 37 = 74 \\ 74 + 37 = 111 \\ 111 + 37 = 148 \\ \\ a = 37 \\ d = 37 \\ \\ T_{1} = a = 37 \\ T_{2} = a + d = 37 + 37(37 \times 1) = 74 \\ T_{3} = a + 2d = 37 + 74(37 \times 2) = 111 \\ T_{4} = a + 3d = 37 + 111(37 \times 3) = 148$