Question

An HCl molecule has rotational, translational and
vibrational motions. If the rms velocity of HCI
molecules in its gaseous phase is ī, m is its
mass and kg is Boltzmann constant, then its
temperature will be :​

Answer 1

The temperature will be T = mv^2/3K

Explanation:

According to question an HCl molecule has rotational, translational and

vibrational motions.

Given data:

rms velocity  = V

Mass of HCL molecule = m

Boltzmann constant = Kb

Solution:

According to equitation energy theorem

1/2 m {(V(rms)^2 } = 3 x 1/2 KbT

T = mv^2/3K

Thus the temperature will be T = mv^2/3K

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