Question

An hour after Aishwarya started from her
college towards Ananya's home, a
distance of 53 km, Ananya started from
her home on the same road towards
Aishwarya's college. If Aishwarya's speed
was 4 km per hour and Ananya's was
3 km per hour, how many km from
Ananya's home did the two meet ?​

Answer 1

Step-by-step explanation:

pahale yeh bata yeh Ananya kon hain number deha toh answer bata dunga LMAO

Answer 2

The distance travel by Aishwarys is 30.2 km

The distance travel by Ananya is 19.8 km

Step-by-step explanation:

Given as :

The distance between Aishwarya and Ananya home  = D = 53 km

Let The distance travel by Aishwarys = d km

Let The distance travel by Ananya = D - d = ( 53 - d ) km

The speed of Aishwarya = S = 4 km/h

The speed of Ananya = s = 3 km/h

The time taken by both when they meet = t hour

According to question

Time = $\dfrac{Distance}{Speed}$

So, For Aishwarys

t = $\dfrac{d}{S}$

Or,  t =   $\dfrac{d km}{4 km/h}$

Or,   t = $\dfrac{d}{4}$  hours             ...........1

So, For Ananya

t = $\dfrac{53-d}{s}$

Or,  t =   $\dfrac{(53-d) km}{3 km/h}$

Or,   t = $\dfrac{53-d}{3}$  hours             ...........2

From eq 1 and eq 2

$\dfrac{53-d}{3}$  =  $\dfrac{d}{4}$

Cross multiplication

4 ( 53 - d ) = 3 d

Or,  212 - 4 d = 3 d

Or,  7 d = 212

∴        d = $\dfrac{212}{7}$

i.e      d = 30.2 km

So, The distance travel by Aishwarys = d = 30.2 km

And The distance travel by Ananya = D - d = ( 53 - 30.2 ) = 19.8 km

Hence, The distance travel by Aishwarys is 30.2 km

And The distance travel by Ananya is 19.8 km  Answer