Question

an hydrogen atom initially in its ground state n=1 level absorb a photo and end up n= 4. what is the frequences of photons?

Answer 1

Answer:

3.1×10^15 herz

Explanation:

For ground level, n1=1.

E1=−13.67/n12=13.67eV

The atom is excited to higher level, n2=4.

E2=−13.67/n22=13.67/16 eV

E=E1−E2=hc/λ

λ=E1−E2hc

⇒13.67−1613.676.6×10−34×3×108

⇒λ=97nm

c=λν

⇒ν=3.1×1015Hz