Question

An ice-berg floating partly immersed in sea water of density 1.03 g/cm³. The density of ice is 0.92 g/cm³. The fraction of the total volume of the iceberg above the level of sea water is (a) 8.1% (b) 11% (c) 34% (d) 0.8%

Answer 1

Explanation:

$\rho =$density of iceberg $= 0.92$

$\sigma =$density of seawater $= 1.03$

let $\eta =$fraction of iceberg submerged

then , volume of iceberg submerged = $\eta V$

$\rho V g = \eta \sigma V g$

thus $\eta = \frac{\rho}{\sigma}$

We find $\eta = 0.893203...$ which is the fraction of the iceberg submerged.

thus the fraction of iceberg outside $= 1 - \eta = 0.10679...$

The percent is 10.68%

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