An ice berg of density 900 kg/m3 is floating in water of density 1000 kg/m3. the percentage of volume of ice-cube outside the water is
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Density of ice outside = 1000 - 900
= 100kg/m3
% of ice outside = 100/1000 × 100
= 10%. Ans
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= 100kg/m3
% of ice outside = 100/1000 × 100
= 10%. Ans
If you like brainliest please
Visit YouTube Channel 'Pfrozen'
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