Question

An ice cream cone has a hemispherical top. If the height of the conical portion is 9 cm and radius 2.5 cm , find the volume of ice creams in 10 such cones.

Answer 1

it is very easy

Step-by-step explanation:

for finding volume of ice cream

we will find volume of cone + volume of hemisphere

Answer 2

Final Answer:

The volume of the ten ice cream cones, each having a hemispherical top with a height of the conical portion of 9 cm and a radius of 2.5 cm, is $915.833\;cm^3$.

Given:

An ice cream cone has a hemispherical top.

The height of the conical portion is 9 cm and the radius is 2.5 cm.

To Find:

The volume of ice creams in 10 such cones.

Explanation:

These points are required for solving the present problem.

• The volume of a hemisphere is $=\frac{2}{3} r^3\;cm^3$.
• The volume of a cone is $=\frac{1}{3} \pi hr^2\;cm^3$

Step 1 of 5

From the given problem, write the following parameters.

• The radius of the hemispherical top is $=2.5\;cm$.
• The radius of the ice cream cone is $=2.5\;cm$.
• The height of the ice cream cone is $=9\;cm$.

Step 2 of 5

The area of the ice cream cone is

$=\frac{1}{3} \pi hr^2\\=\frac{1}{3} \times\pi \times 9\times 2.5^2\\\=58.875\;cm^3$.

Step 3 of 5

The area of the hemispherical top is

$=\frac{2}{3}\pi r^3\\\\=\frac{2}{3}\times \pi \times 2.5^3\\\\=32.7083\;cm^3$

Step 4 of 5

So, the total volume of one cone is

$=58.875+32.7083\\=91.5833\;cm^3$

Step 5 of 5

Thus, the total volume of ten cones is

$=91.5833\times 10\\=915.833\;cm^3$

Therefore, the required volume of the ten ice cream cones with the said dimensions is $915.833\;cm^3$

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