Math, asked by adetolalydia, 1 month ago

An ice cream Cone is filled with ice-cream such that a hemisphere of ice cream is mounted on top. The base of the hemisphere of the ice-cream and the top of the cone are of the Same radius. (take pie =22÷7).
a).If the vertical height of the cone is 4 times its radius(r), show that the total volume of the ice cream is
2\pi \: {r}^{3}
b.) How many ice creams each of radius. 1.75cm can be made from a cylindrical container of radius 14cm and height 32cm which is 3/4 full of ice cream.
pls i need it urgently, show workings thanks and figure ​

Answers

Answered by abhishekonweb90
2

Answer:

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Step-by-step explanation:

Radius of cone =r of h.s

r=3.5

Total height =12.5

Total h of cone −h.s.

12.5−3.5

h of conical =9 cm

V. of ice cream in the cone = volume of conical part +V. of h.s.

=

3

1

πr

2

h+

3

2

πr

3

=

3

1

πr

2

(h+2r)

=

3

1

×

7

22

×(3.5)

2

(9+2×3.5)

=

3

1

×

7

22

×(3.5)

2

(9+7)

=

2

1

×

7

22

×(3.5)

2

×16

V. of ice cream in the cone =205.33 cm

2

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