Question

An ice-cream cone is full of ice cream having radius 5cm and height 10cm. Calculate the volume Of ice-cream provided that its 1/6 part is left unfilled with ice-cream.

Answer 1

Total volume of cone= 1/3πr^2h
=1/3*3.14*5*5*10
=261.67cm^3
Volume unfilled= 1/6*total volume
=1/6*261.67
=43.61cm^3
Therefore volume of ice cream provided. = 261.67 - 43.61
=218.06cm^3

Answer 2

HERE,

IN ORDER TO FIND THE VOLUME OF ICE CREAM PROVIDED WE MUST FIRST FIND THE VOLUME OF THE CONE AND THEN WE WOULD WORK OUT TO FIND THE SAME.

We have,
radius=5cm,height=10cm

$volume \: of \: cone = \frac{1}{3} \pi {r}^{2} h$

$= \frac{1}{3} \times \frac{22}{7} \times {5}^{2} \times 10$

$= \frac{1}{3} \times \frac{22}{7} \times 25 \times 5$

$= \frac{22}{21} \times 125$

$= 130.90sq.cm$

1/6th part of the volume of cone
=1/6×130.90
=21.817sq.cm

volume of ice cream provided
=volume of cone-1/6th part of cone
=130.90-21.817
=109.083sq.cm

thus,
volume of ice cream provided is 109.083sq.cm

$hope \: this \: helps$