Math, asked by 10h25shriman, 3 months ago

An ice-cream seller sells his ice-creams in two
ways:
4.2 cm
Type 1, in a cone of radius 4.2 cm
surmounted by a hemisphere of
same radius.
10.2 cm
Type 2, in a cone of radius 5.6 cm
and height 4 cm surmounted by a
hemisphere of same radius.
5.6 cm
Gauri insisted to have ice-cream in +
first type while her brother Dhruv
decided to have the ice-cream
in second type. From the above
4 cm
information give the answer of
the following questions.
(i) While calculating the volume of the combined
solids, we need:
(a) add the volume of each solid
(b) difference of the volume of both solids
(c) to take same volume of each solid
(d) none of the above.
(ii) How much quantity of the ice-cream Gauri
gets?
(a) 266.11 cm
(b) 232.3 cm
(c) 273.11 cm
3
(d) 292.6 cm
(iii) How much quantity of the ice-cream Dhruv
gets?
(a) 459.12 cm
3
(b) 499.32 cm
(C) 513.12 cm
(d) 519.23 cm
(iv) Out of the two, Gauri and Dhruv who got less
quantity of ice-cream to eat?
(a) Gauri
(b) Dhruv
(c) Both got same quantity (d) None of these.
1700​

Answers

Answered by amitnrw
4

Given : An ice-cream seller sells his ice-creams in two  ways:

Type 1, by Gauri :  in a cone of radius 4.2 cm surmounted by  a Hemisphere of same radius and total height 10.2cm

Type 2 by Dhruv, in a cone of radius 5.6 cm and height 4 cm surmounted by a hemisphere of same radius.  

To Find :  While calculating the volume of the combined solids, we need:

How much quantity of the ice-cream Gauri gets?

How much quantity of the ice-cream Dhruv gets?

Out of the two, Gauri and Dhruv who got less quantity of ice-cream to  

eat?

How much more quantity of ice-cream get by Dhruv?

Solution:

While calculating the volume of the combined solids, we need to add the volume of each solid

Gauri ice-cream

cone of radius 4.2 cm , surmounted by  a hemisphere of same radius. and height = 10.2cm

Hence cone height = 10.2 - 4.2 = 6cm

Volume of cone = (1/3)πr²h  = (1/3)(22/7)(4.2)²6

= 110.88

Volume of Hemisphere = (2/3)πr³ = (2/3)(22/7)(4.2)³

= 155.232

Volume = 110.88 + 155.232 =  266.112 cm³

Gauri gets 266.11 cm³ ice cream

Dhruv   ice-cream

cone of radius 5.6 cm and height 4  cm surmounted by a hemisphere of same radius.

Volume of cone = (1/3)πr²h  = (1/3)(22/7)(5.6)²4

= 131.413

Volume of Hemisphere = (2/3)πr³ = (2/3)(22/7)(5.6)³

= 367.957

Volume = 131.413 + 367.957=  499.37  cm³

Dhruv  gets 499.32 cm³ ice cream

Gauri  gets lesser Quantity

more quantity of ice-cream get by Dhruv = 499.32 - 266.11

= 233.21 cm³

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