Physics, asked by nitinreddykonda898, 10 months ago

An ice cube floats in water. What percentage of volume is outside water. Density of water = 1g// c c, density of ice = 0.9 g// c c.

Answers

Answered by Anonymous
20

Answer:

hello mate..

here's ur answer..

Density of ice outside = 1000 - 900

Density of ice outside = 1000 - 900= 100kg/m3

Density of ice outside = 1000 - 900= 100kg/m3% of ice outside = 100/1000 × 100

Density of ice outside = 1000 - 900= 100kg/m3% of ice outside = 100/1000 × 100= 10%.

hope it helps..

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