an ice cube is floating in a liquid such that the two third part of cube is inside the liquid of density of ice cube is 900 kg/M3 find the density of liquid
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volume of the cube be V and the fraction of cube outside water be f.
Thus, volume of ice inside water = volume of water displaced =(1−f)V
Under equilibrium,
Weight of ice = Weight of water displaced
⟹Vρ iceg=(1−f)Vρ waterg
⟹(1−f)= 9/10
⟹f= 1/ 10
Thus, the percentage of volume outside water =10%
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