An ice cube of density 0.9 g/cm³ floats in water of density 1 g/cm³. The percentage of volume of the ice cube outside water is
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Answer: The forces acting on the ice must balance each other.
Hence buoyant force acting upwards = Weight of the ice
Vimm ρg= Vdg
Vimm /v = d/ρ = 0.9
Hence, the fraction of ice outside water =1−0.9=0.1
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