Question

an ice cube of side 14 cm has a hole of volume 44cc inside .if the density of ice is 0.9g/cc, find the mass of ice ?also find the volume of the water formed when ice melts completely ?


answer will come 2.43kg or 2430 c.c

how to do the sum

Answer 1

Step-by-step explanation:

l=14cm,v=44cc,d=0.9g/cc m=?

Answer 2

The mass of the ice will be 2.46 Kg and the volume of the water formed when the ice melts completely will be $2.7$ × $10^{-3}$ $m^{3}$

Give:

The side of an ice cube = 14 $cm$

The volume of a hole inside the ice cube = 44 $cm^{3}$

The density of the ice cube = 0.9 $g/$$cm^{3}$

To Find:

The mass of the ice cube and the volume of the water formed when the ice melts completely.

Solution:

The answer to this question can be found easily as given below,

We know that,

$Density (\delta)$ = $\frac{Mass (m)}{Volume (v)}$

Here,

The volume of a cube = $a^{3}$

It is given that the side of the cube = 14 cm

Then,

The volume of the cube,

= $a^{3}$

= $14^{3}$

= 2744 $cm^{3}$

Then,

Mass of the ice cube (m) = Density ($\delta$) x Volume (v)

= 0.9 x 2744

= 2469.6 g

= 2.46 Kg

It is already given that there is a hole inside the ice cube of volume

= 44 $cm^{3}$

We have the volume of cube = 2744 $cm^{3}$

Then,

The volume of water formed when the ice melts completely will be

= The volume of the cube – The Volume of the hole inside the cube

= 2744 $cm^{3}$ – 44 $cm^{3}$

= 2700 $cm^{3}$

= 0.0027 $m^{3}$

= $2.7$ × $10^{-3}$ $m^{3}$

Hence, the mass of the ice cube is 2.46 Kg and the volume of the water formed when the ice melts completely is $2.7$ × $10^{-3}$ $m^{3}$

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