An ice floats in the water with 9/10th of its volume below the water. What is the density of Ice. Please I need genuine answers.
Answers
Answer:
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Explanation:
Ice floats in water with about nine tenths of its volume submerged. What is the fractional volume submerged for an iceberg floating on a fresh water lake of a planet whose gravity is ten time that of the Earth’s?
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In order to float an object must displace enough volume of water to match its mass. Assuming a uniform density for both ice and water, that would mean
M(ice) g= 9/10 V(ice)*ρ(water)*g
M(ice)=V(ice)*ρ(ice) so we get
Vi*ρi*g= 9/10*Vi*ρw*g => ρi=9/10ρw
Now on the other planet we’ll call the fractional submergence “x”
Mi*10g=Vi*ρi*10g=9/10*ρw*Vi*10g= x*Vi*ρw*10g => x=9/10. It’s the same.
Should we have expected this? Of course we should. Even though ice weighs 10 times more under the new gravity, so does the water it displaces. Buoyant force is proportional to the weight of the displaced liquid. Weight means mass times acceleration of gravity. So in short the ice weighs 10 times more but it’s pushed up by a force 10 times stronger
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