Question

An ice piece floats in water with 9/10th part of the ice in the water. Calculate the density of the ice piece

Answer 1

Answer:

0.9

Explanation:

if object is partially submerged

B=mg

=> Buoyancy (B)=vdg (d =density of water, v=volume of liquid displaced g= gravity)

vdg=mg

since , density of solid(p)=mass of solid/vol of solid(x)

m =px

vdg =pxg

v/x=p/d

since v/x is 9/10

and density of water is 1

= > 9/10=p/1

p=0.9