Physics, asked by pawanlahera, 8 hours ago

An iceberg floats in fresh water with a part of it outside the water surface.Use density of water is 1000kg/m3 and density of ice is 900kg/m3​

Answers

Answered by deveshwarans06
0

Answer:

Let the volume of the cube be V and the fraction of cube outside water be f.

Thus, volume of ice inside water = volume of water displaced =(1−f)V

Under equilibrium,

Weight of ice = Weight of water displaced

⟹Vρ

ice

g=(1−f)Vρ

water

g

⟹(1−f)=

10

9

⟹f=

10

1

Thus, the percentage of volume outside water =10%

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