Physics, asked by ashvikahgoel, 21 hours ago

An iceberg is floating in water with 1/10 th of its volume above the surface. When floated
in seawater 1/9 th remains above its surface. Calculate the density of the iceberg and that of the seawater.

Answers

Answered by shreyadikshit56
0

Answer:

The displaced water should provide the buoyancy force that equals the weight of the iceberg: icebergvolume×900kg/m

3

×g=displacedvolume×1030kg/m

3

g.

Therefore, Displaced volume/iceberg volume =900/1030=90/103.

Hence, 90/103 of the volume is under water and 13/103 of the volume is above the water.

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