An iceberg is floating in water with 1/10 th of its volume above the surface. When floated
in seawater 1/9 th remains above its surface. Calculate the density of the iceberg and that of the seawater.
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Answer:
The displaced water should provide the buoyancy force that equals the weight of the iceberg: icebergvolume×900kg/m
3
×g=displacedvolume×1030kg/m
3
g.
Therefore, Displaced volume/iceberg volume =900/1030=90/103.
Hence, 90/103 of the volume is under water and 13/103 of the volume is above the water.
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