Question

an iceberg is floating partially immersed in sea water.The density of sea water is 1.03gm/cm^3 and that of ice is 0.92 gm/cm^3.What fraction of total volume of iceberg above the level of sea water
a) 9.6%
b) 10%
c) 10.6%
d) 11%

Answer 1

Volume above water = V
volume below water = V'
seawater density x V' = ice density x V 
1.03 x V' = 0.92 x V 
V'/V = fraction below water = 0.89

Fraction above water = 1 - fraction below water
= 0.11

Answer 2

Mg=Vin* rho* g or Vin*rho*g

Or Vin=(rho of water/rho of ice)*V

So Vout=V-Vin=V(1-rho of water /rho of ice)

Or fout=Vout/V=(1-rho of water/rho of ice)

=(1-0.92/1.03)=0.11/1.03=0.106 or fout =10.6%