An Icecream is in the form of the hemisphere
mounted on a cone The diameter of the
common base is 12 and height of the cone is 8cm
Determine
the surface area of the Ice-cream
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Answer:
Radius of cone =r of h.s
r=3.5
Total height =12.5
Total h of cone −h.s.
12.5−3.5
h of conical =9 cm
V. of ice cream in the cone = volume of conical part +V. of h.s.
=
3
1
πr
2
h+
3
2
πr
3
=
3
1
πr
2
(h+2r)
=
3
1
×
7
22
×(3.5)
2
(9+2×3.5)
=
3
1
×
7
22
×(3.5)
2
(9+7)
=
2
1
×
7
22
×(3.5)
2
×16
V. of ice cream in the cone =205.33 cm
2
.
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