Question

An ideal battery sends a current of 5 A in a resistor. When another resistor of 10 Ω is connected in parallel, the current through the battery is increased to 6 A. Find the resistance of the first resistor.

Answer 1

Answer:

2 ohms

Explanation:

v=5r

5r=(10r/10+r)6

by solving we get 2

Answer 2

The resistance of the first resistor = 2Ω.

Explanation:

From the given, we can say that

R1=R, i1= 5A

R2= 10R/10+R, i2 = 6A

We know that V = iR

Since voltage is constant  

I1R1 = i2R2

(10+R)5 = 60

Hence from the above equation

Resistance (R) = 2 Ω.(ohm)

R = Resistance of the circuit

V = Voltage drop across the resistor

I = Maximum current flowing in the circuit.