Question

An ideal carnot engine, whose efficiency is 40% receives heat at 500 K. If its efficiency is 50%, then the intake temperature for the same exhaust temperature is (a) 600 K (b) 700 K (c) 800 K (d) 900 K

Answer 1

Answer:

NEW SOURCE TEMPERATURE ( T³ ) =

600 K

OPTION A

Explanation:

★ CARNOT ENGINE ★

★ GIVEN ;

» Source Temperature ( T¹ ) = 500 K

» Initial Efficiency ( ẞ¹) = 40 %

» Final Efficiency ( ẞ² ) = 50%

★ SINK TEMPERATURE ( T² ) = ???

★ SOURCE TEMPERATURE ( T³ ) = ???

_____ [ BY USING FORMULA ] ____

$\beta \: = \: 1 \: - \: \frac{ {T}^{2} }{ {T}^{1} }$

★ ẞ¹ = [ 1 - T² / T¹ ]

» 0.4 = [ 1 - T² / 500 ]

» 0.4 = [ 500 - T² / 500 ]

» 200 × 0.4 = 500 - T²

★ T² = 300 K [ SINK TEMPERATURE ]

________________________________________

[ ★ ẞ² = 1 - T² / T³ ]

» 0.5 = 1 - T² / T³

» 0.5 = 1 - 300 / T³

» 0.5 = [ T³ - 300 / T³ ]

» 0.5 T³ = T³ - 300

» 0.5 T³ = 300

★ T³ = 600 K ★

________________________________________

ANSWER :- NEW SOURCE TEMPERATURE HAVING 50% EFFICIENCY IS ;

[ T³ = 600 Kelvin ]

Answer 2

Answer:

600k

Explanation:

refer the attachment for detailed answer.

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