Question

An ideal engine which works between 27°C & 227°C takes 100 calorie of heat in one cycle. Calculate the work done in one cycle ?

Answer 1

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11th

Physics

Thermodynamics

Engines and Cycles

An ideal engine which works...

PHYSICS

An ideal engine which works between 27

∘

C & 227

∘

C takes 100 calorie of heat in one cycle. Calculate the work done in one cycle.

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ANSWER

Given:

Temperature of source, T

1

=27°C=(27+273)K=300K

Temperature of sink, T

2

=227°C=(227+273)K=500K

Heat, Q

1

=100cal

To find:

Work done in one cycle, W=?

We know efficiency of an engine can be found by the following formula,

η=

T

1

T

1

−T

2

=

500

500−300

=0.4

Again, efficiency is also equal to following formula,

η=

Q

1

Q

1

−W

⟹0.4=

100

100−W

⟹40=100−W

⟹W=60cal

Hence the work done in one cycle us 60cal.