Question

an ideal gas at a pressure of 1 atmosphere and temperature of 27 degrees Celsius is compressed adiabatically until its pressure becomes 8 times the intial pressure then the final temperature is​

Answer 1

Answer:

Final temperature ,$T_{2} =543.5 Kelvin$

Explanation:

Since we know that  adiabatic process is that process in which heat transfer is zero.

It is given the question that the process is adiabatic, so no heat is transfer.

It is also given that the final pressure becomes 8 times with respect to initial pressure.

$\frac{P_{2} }{P_{1} } =8$.....................(1)

We know the adiabatic relationship between temperature and presuure.

$\frac{T_{2} }{T_{1} }=(\frac{P_{2} }{P_{1} }) ^{\frac{\gamma -1}{\gamma } }$...............(2)

For air $\gamma =1.4$

$T_{1} =300K$....................(3)

Using (1), (2) and (3) we get

So, final temperature ,$T_{2} =543.5 Kelvin$

Answer 2

Explanation:

327 is the answer

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