An ideal gas at has a pressure of 760 mm of Hg. The gas is compressed isothermally (without change in temperature) until its volume is halved. The final pressure of the gas will be:
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Let initial pressure, volume and temperature be P, V and T respectively.
∴ P
2
=2P
For isothermal process : P
2
V
2
=P
1
V
1
(2P)V
2
=PV ⟹V
2
=
2
V
For adiabatic process : P
2
V
2
γ
=P
3
V
3
γ
(Given γ=1.4)
⇒2P(
2
V
)
1.4
=P
3
V
1.4
⇒ 2(
2
1
)
1.4
=
P
P
3
⇒2×0.38=
P
P
3
⇒
P
P
3
=0.76
Thus, P
3
:P=0.76:1
I hope this helps you
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