Question

An ideal gas expands from 1.5 to 6.5 litre against as constant pressure of 0.5 atm and during this process the gas also absorbs 100j of heat .the change in the internal energy pf the gas

Answer 1

∆U = q + P∆V

P = 0.5 atm = 0.5*10^5 Pa
∆V = V2-V1 = 6.5-1.5 = 5 L = 5*10^-3 m3
q = +100J

∆U = 100 - 0.5*10^5(5*10^-3) = -150J