An ideal gas expands from the volume of 1 × 10–3 m3 to 1 × 10–2 m3 at 300 K against a constant pressure at 1 × 105 Nm–2. The work done is
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QUESTiON :-
- An ideal gas expands from the volume of 1 × 10–3 m³ to 1 × 10^–2 m³ at 300 K against a constant pressure at 1 × 105 Nm^–2. The work done is
ANSWER :-
- -900 J
EXPLAiNATiON :--
- w = – P ∆ V
- w = – (1 × 10⁵ Nm^–2)
(1× 10^–2 m³ – 1 × 10^–3 m³)
- w= –10⁵ (10^–2 – 10^–3) Nm
- w = – 10⁵ (10 – 1) 10^–3) J
- w = – 10⁵ (9 × 10^–3) J
- w = –9 × 10² J
- w = –900 J
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Answered by
0
Answer:
Work done, W=−PΔV =−10
5
(10
−2
−10
−3
)N−m
W=−(1000−100) N.m=−900 J
Explanation:
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