An ideal gas goes from state A to state B through three different processes 1, 2 and 3 as shown in figure. If the work done during these processes is W₁, W₂ and W₃ respectively. Then
(A) W₁ > W₂ > W₃
(B) W₁ = W₂ = W₃
(C) W₁ < W₂ < W₃
(D) W₁ > W₃ > W₂
Attachments:
Answers
Answered by
3
heat absorbed is q3>q2>q1 therefore the work done is constant,i.e. w1=w2=w3.
Similar questions