Question

An ideal gas has a volume of 15ml, a temperature of 20C and a pressure of 100kPa. The volume of the gas is reduced to 5ml and the temperature is raised to 40C. What is the new pressure of the gas?

Answer 1

Answer:

320.5 kPa is the new pressure of the ideal gas after the compression in volume by a factor of 3 .

Explanation:

An ideal gas follows:   P V = n R T

or    P₁ V₁ / T₁ = P₂ V₂ /T₂

So  P₂ = P₁ V₁ T₂ / (T₁ V₂)

Given P₁ = 100 kPa , V₁ = 15 ml = 15 * 10⁻⁶ m³,  T₁ = 293⁰K , T₂ = 313⁰K, V₂= 5 * 10⁻⁶ m³.

    V₁ = 3 V₂

     P₂ = 100 *10³ * 3 * 313/293 = 3.205 * 10⁵ Pa