Question

An ideal gas has an adiabetic exponent 'gamma'. It expands according to the law P=aV where 'a' is a constant. For this process, Bulk modulus of the gas is


14. An ideal gas has adiabatic exponent γ . It expands according to the law P = αV, where α is constant. For this process, the Bulk modulus of the gas is(1) P (2) Pα(3) αP (4) (1 - α)P

Answer 1

The Bulk Modulus of the gas is K = P.

Option (1) is correct.

Explanation:

If the equation is

P = aV

or

PV^-1 = a ........α = (-1)

Then we know from Laplace law.

K = αP

Or K = (-1) x av     [ From equation (1)and (2) ]

K = - aV

or K = (-1) x P

K = -P

In the bulk modulus

K = P

Hence the Bulk Modulus of the gas is K = P.

Also learn more

What is the edge of a cube whose volume is 9000cm^3?

https://brainly.in/question/14481843

Answer 2

Answer:1)P

Explanation:

If pv =constant.. So diferentitate both sides.

VdP + PdV=0

Now,

dP/dV=-P/V ....... (I)

We know that:

B=dP/dV/V = dp/dv xV

USING equation (I)

B=-P/VxV =-P

But the question asks for the value of Bulk modulus so we can neglect the negative sign.

Hence B=P.. ✌️