Chemistry, asked by gurmangrewal1109, 1 month ago

An ideal gas having 2 moles (fixed) is subjected to the changes as shown is (P–V) diagram. Select the
correct option(s) from the following diagram

Answers

Answered by sourav0667
0

Answer:

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An ideal gas is taken from state A (Pressure P, Volume V ) to the state B (Pressure P/2, Volume 2V) along a straight line path in PV diagram as shown in the adjacent figure.

Select the correct statement (s) among the following:

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This question has multiple correct options

Hard

Solution

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Correct options are A) , B) and D)

Work done = Area under P−V graph

As A

1

>A

2

∴W

given process

>W

isothermal process

Thus (A) is correct.

In the given process P−V equation will be a straight line with negative slope and positive intercept, i.e.,

P=−aV+b

Here, a and b are positive constants.

P=−aV+b

⇒PV=−aV

2

+bV

⇒nRT=−aV

2

+bV[∵PV=nRT(From ideal gas equation)]

⇒T=

nR

1

(−aV

2

+bV)

The above equation is of parabola.

Thus (B) is correct.

T=

nR

1

(−aV

2

+bV)

dV

dT

=0

nR

1

(−2aV+b)=0

⇒−2aV+b=0

⇒V=

2a

b

Now,

dV

2

d

2

T

=−2a=−ve

∴T has some maximum value.

Now, from ideal gas equation,

T∝PV

∵(PV)

A

=(PV)

B

∴T

A

=T

B

We conclude that temperatures are same at A and B but in between the temperature has a maximum value.

Hence in going from A to B, the temperture will first increase to a maximum value and then decrease.

Thus (D) is correct.

Answered by arshaarunsl
0

Answer:

Correct options are A),B) and D)

Explanation:

Work done=Area under P--V graph

As A1>A2

Therefore, W given process>W isothermal process

Thus A is correct

In the given process P--V equation will be a straight line with negative and positive intercept,

P= -aV+b

nRT= -aV²+bV

T=1/nR (-aV²+bV)

Eqn is parabola.

Thus B is correct.

T=1/nR(-aV²+bV)

dT/dV=0

1/nR(-aV²+bV)=0

V=b/2a

d²T/dV²=-2aV+b=-ve

T has max value.

From ideal gas equation, T∞PV

(PV)A=(PV)B

TA=TB

We conclude that temperature are same at A and B and also have maxi value in between them.

Hence in going from A and B, the temperature will first increase to maxi value and then decrease. Thus (D) is correct.

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