An ideal gas heat engine operates in a carnot cycle between 227∘C and 127∘C. It absorbs 6 kcal at the higher temperature. The amount of heat (in kcal) converted into work is equal to -
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1
Answer:
Yes
Explanation:
So,
Taking ∅ =25°
We can assume ΔKE to be equal to work
Now Fsin∅ ∝ U
However πC° is equal to U
⇒F ∝ U ∝ C
Taking constant proportionality are K
You get he rest ya?
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An ideal gas heat engine operates in a Carnot cycle between 227∘C and 127∘C. It absorbs 6 Kcal at the higher temperature. The amount of heat (in Kcal) converted into work is equal to 1.2 Kcal.
- The heat engine works between the temperatures 227∘C (500K) and 127∘C (400K).
- So, Efficiency of the engine = 1 - (400/500) =0.2
- Now, we know, efficiency = Work done / Heat absorbed
- So, work done (W) = Heat absorbed * efficiency = 6 * 0.2 =1.2 Kcal.
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