An ideal gas in initial state (1atm, 273k,22.4L) is heated to 546k . The volume of the gas becomes 4.48L . The final pressure of the gas is
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Answered by
7
Answer:
The final pressure of the gas will be 10 atm.
Explanation:
P1=1 atm
P2=?
V1=22.4L
V2=4.48L
T1=273K
T2=546K
According to combined gas equation,
(P1V1)/T1= (P2.V2)/T2
=>1*22.4/273 = P2.4.48/546
=> 22.4*546/273*4.48=P2
=>224*546*10/273*448 = P2
=> 10 atm=P2
Answered by
0
Answer:
10 atm
Explanation:
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