An ideal gas is allowed to expand from 1 L to 10 L against a constant external pressure of 1bar. The work done in kJ is:
(A) – 9.0 (B) – 0.9
(C) – 2.0 (D) + 10.0
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Answer:
answer is +10.0 ......
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The work done in kJ is (B) – 0.9
- Given :
Initial volume, V1 = 1 L
Final volume, V2 = 10 L
Pressure = 1 bar
- Work done = - PΔV
W = - P × (V2 - V1)
W = - 1 × (10 - 1)
W = -9 bar L
W = -9 × 10⁵ × 10⁻³ Pa m³
W = -9 × 10² J
W = -900 J
W = -0.9 kJ
- So the correct answer is option (B)
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