Question

an ideal gas is at a temperature t having molecules each of mass m. if k is the bolt man's constant and 2kt/m = 1.40*10^5 m²/s². Find the percentage of the fraction of molecules whose speed lie in the range 324 m/s to 326 m/s.

Answer 1

Answer:

The answer is 0.55 %.

Explanation:

v = √ 3KnT / m

1.5 x 2kT/ m = 2.1 x 10^5 m^2/s^2

324 = √ 2.1 x 10^5  x n

324  = 2.1 x 10^5  x n

n = 0.49988

326 =  √ 2.1 x 10^5  x n'

326 =   2.1 x 10^5  x n'

n' = 0.50607

Percentage = 0.50607 -  0.49988 / 1 x 100

                  = 0.55 percent