An ideal gas is contained in a cylinder at pressure P1 and temperature T1. The initial moles of the gas is n1. The gas leaks from the cylinder and attains a final pressure P2 and temperature T2. The new moles of the gas present in the cylinder is
Answers
Given:
An ideal gas is contained in a cylinder at pressure P1 and temperature T1. The initial moles of the gas is n1. The gas leaks from the cylinder and attains a final pressure P2 and temperature T2.
To find:
New moles of gas in cylinder?
Calculation:
Since the gas is ideal , we can say that it will follow the IDEAL GAS EQUATION:
Now, at different system conditions:
Now, divide the Equations:
So, final answer is:
Explanation:
Since the gas is ideal , we can say that it will follow the IDEAL GAS EQUATION:
P1 \: V1 =( n1)R \: (T1)P1V1=(n1)R(T1)
Now, at different system conditions:
P2 \: V2 = (n2)R \: (T2)P2V2=(n2)R(T2)
Now, divide the Equations:
\implies \: \dfrac{P2 \: V2}{P1 \: V1} = \dfrac{(n2) \: T2}{(n1) \: T1}⟹
P1V1
P2V2
=
(n1)T1
(n2)T2
\implies \: n2 = \bigg( \dfrac{P2 \: V2}{P1 \: V1} \times \dfrac{(n1)(T1)}{T2} \bigg)⟹n2=(
P1V1
P2V2
×
T2
(n1)(T1)
)
So, final answer is:
\boxed{ \bf\: n2 = \bigg( \dfrac{P2 \: V2}{P1 \: V1} \times \dfrac{(n1)(T1)}{T2} \bigg)}
n2=(
P1V1
P2V2
×
T2
(n1)(T1)
)