Question

An ideal gas is found to obey an additional law VP² = constant. The gas is initially at temperature T and volume V. When it expands to a volume 2 V, the temperature becomes(a) T/√2(b) 2T(c) 2T√2(d) 4T

Answer 1

ur answer is option no b

Answer 2

Answer:

Explanation:

VP² = constant ( Given) -- eq 1

According to Lussac's pressure law -

P = nRT/V

Substituting the value in Eq 1 -

= nRTV²/v = constant

Since, n and R are constant, above equation becomes-

TV = constant-- eq 2

Since the gas is expanding from the initial volume, V1 to final the volume V2 by 2 units, it will become -

V2 = 2v1

Thus, by using equation 2

T1V1 = T2V2

T1V1 = T2(2V1)

T2 = T√2