Question

an ideal gas is in a sealed cylinder and had initial volume of 2.60L. at constant pressure it's cooled to 23 degrees Celsius, where it's final volume is 1.75L. What was the initial temperature? ​

Answer 1

Explanation:

We use Charles' Law:

V

1

T

1

=

V

2

T

2

Plug in the values:

2.35

L

T

1

=

1.75

L

291

K

Solve the algebra:

2.35

L

x

291

K

=

683.85

L

⋅

K

683.85

L

⋅

K

x

1

1.75

L

=

391

K

You can convert it back to degrees Celsius by subtracting 273.