Physics, asked by swarupslp, 9 months ago

An ideal gas is subjected to a thermodynamic process PV-I = 0.4 where P is pressure in pascal and Q
Vis volume in (metre). What is the slope of the P-V curve with volume plotted aganist x-axis at
V=1 m ?​

Answers

Answered by CarliReifsteck
9

Given that,

An ideal gas is subjected to a thermodynamic process

PV^{2.5}=0.4

Volume = 1 m³

We know that,

The P-V curve is \dfrac{dP}{dV}.

We need to calculate the slope of the P-V curve

Using given equation

PV^{2.5}=0.4

PV^{\frac{5}{2}}=\dfrac{2}{5}

P=V^{-\frac{5}{2}}\times\dfrac{2}{5}

On differentiating w.r.to V

\dfrac{dP}{dV}=\dfrac{2}{5}\times(-\dfrac{5}{2})\times V^{-\dfrac{7}{2}}

Put the value of V

\dfrac{dP}{dV}=\dfrac{2}{5}\times(-\dfrac{5}{2})\times(1)^{-\dfrac{7}{2}}

\dfrac{dP}{dV}=-1

Hence, The slope of the P-V curve is -1.

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