Physics, asked by kakshay2500, 1 year ago

An ideal gas is taken around the cycle abc 5j work done by the gas in process c to a

Answers

Answered by smartysurya773389
1

Explanation :

In the cyclic process : △=0

△Q=△W

△W=WA→B+WB→C+WC→A

WB→C=0 (Volume remains constant)

WA→B=P(V2−V1) (Pressure remains constant)

=10(2−1)=10J

Therefore , 5=10+WC→A

WC→A=−5J

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