Question

An ideal gas is taken through a cycle A-B-C-A as shown in figure.If net heat supplied to the gas in the cycle is 5J the work done by the gas in the process C-A

Answer 1

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Answer : −5J
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Explanation :
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In the cyclic process : △=0
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△Q=△W△Q=△W
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△W=WA→B+WB→C+WC→A△W=WA→B+WB→C+WC→A$<b><font face=copper black size =4 color=orange>$
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WB→C=0WB→C=0 (Volume remains constant)
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WA→B=P(V2−V1)WA→B=P(V2−V1) (Pressure remains constant)

=10(2−1)=10J=10(2−1)=10J

Therefore , 5=10+WC→A5=10+WC→A

WC→A=−5J

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Answer 2

Explanation:

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