An ideal gas mixture filled inside a balloon expands according to the relation pv 2/3 = constant. the temperature inside the balloon is
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I think it would be 40 degree
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Temperature increases with increase in volume
Explanation:
Given that a balloon is filled with an ideal gas mixture and expands according to the relation PV^2/3 = constant.
So PV^(2/3) = constant -------------------- (1)
where P is pressure and V is volume.
As per the ideal gas law, we have PV = RT
where P is pressure, V is volume, T is temperature and R is the ideal gas constant.
So P = RT / V -------------------- (2)
Substituting (2) in (1), we get:
(RT / V) * V^2/3 = constant
RT*V^(-1/3) = constant
Since R is constant, we conclude that T α V^(1/3).
Temperature is directly proportional to volume. So with the increase in volume, temperature of the gas inside the balloon increases.
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