Question

An ideal gas occupies a volume of 2m3 at a pressure of 3106 pa. The energy of the gas is :

Answer 1

volume of gas, V = 2m³

pressure of gas, P = 3 × 10^6 Pa

[ 1Pa = 1N/m² ]

so, pressure of gas, P = 3 × 10^6 N/m²

use formula, $E=\frac{3}{2}PV$

where E denotes energy of gas.

= 3/2 × 3 × 10^6 × 2 J

= 3 × 3 × 10^6 J

= 9 × 10^6 J

hence, energy of gas is 9 × 10^6 J

Answer 2

For Calculating energy,

we know the Formula,

Energy = 3/2 nRT

or Energy =  3/2 PV

Actually, there will now always be three, there will sometimes be f.  But we always uses three while solving such questions as mathematical proof tolds this as 3 only.

Energy = 3/2 × 3160 × 2

∴  Energy = 9480 J.

Note : Energy here means the  Change in Internal Energy or you can also say it as Kinetic Energy.

Hope it helps.