An ideal gas occupying a volume of 2 dm
and a pressure of 5 bar undergoes isothermal
and irreversible expansion against external
pressure of 1 bar. The final volume of the
system and the work involved in the process
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10
The final volume of the system is 10 dm^3 and the work done is - 800 J.
Explanation:
Vf=P1V1Pf
=(5bar)×(2dm)3 / 1bar = 10 dm3
Work "w" = –Pext(Vf–Vi)
= – (1bar)(10–2) dm3
= –1×105Pa×8×10–3m3
= - 800J
Thus the final volume of the system is 10 dm^3 and the work done is -800 J.
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