Chemistry, asked by Anonymous, 3 months ago

An ideal gas undergoes an isothermal expansion at 77ºC increasing its volume from 1.3 to 3.4 L. The entropy change of the gas is 24 J/K. How many moles of gas are present?

Answers

Answered by answerFast28
0

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Answered by Anonymous
2

Explanation:

Solution:-

To obtain the number of moles n are present in the gas, substitute 24 J/K for ΔS, 8.31 J/mol. K for R, 3.4  L for Vf and 1.3 L for Vi in the equation,

n = ΔS/ (R ln Vf/Vi)

 = (24 J/K) / (8.31 J/mol. K) (ln 3.4 L/1.3 L)

= (24 J/K) / (8.31 J/mol. K) (ln (3.4/1.3))

= 3.00 mol

From the above observation we conclude that, the number of moles n are present in the gas would be 3.00 mol.

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