Question

An ideal inductor takes a current of 10a when connected to a 125v,50hz

Answer 1

Voltage across inductor is

$V_L = 125 volts$

frequency of AC voltage is

$f = 50 Hz$

current in ideal inductor is

$i = 10 A$

now as per our formula same as ohm's law

$V = i*X_L$

now plug in all values

$125 = 10*x_L$

now on solving above equation we have

$x_L = 12.5 ohm$

now by the formula

$2\pi f L = 12.5$

L = 0.04 H

so inductance L = 0.04 H