Physics, asked by subhranshukashyap, 2 days ago

An ideal liquid is flowing through a pipe kept on horizontal floor as shown in figure. The flow is streamline flow. The pressure at two points are indicated, then​

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Answered by pv4446870
0

Answer:

Solution

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Correct option is B)

area of A=2 mm

2

area of B=4 mm

2

velocity at A,V

A

=4 m/s

let velocity at B,V

B

liquid passed through any cross section

within a Second is constant

A

1

V

A

=A

2

V

B

2×4=4×V

B

or V

B

=2 m/s

Correct option is (B).

Answered by sriramvsynergy
0

The appropriate fluid flows into a pipe kept in a horizontal position as shown in the figure and the flow is normal flow, pressure at two points is shown, are:

  • Flow the appropriate fluid (laminar flow) through a pipe of different diameters.
  • The minimum size and diameter of the pipes is 6.4 cm and 4.8 cm, respectively.
  • The minimum velocity and maximum volume of liquid in this pipe is a. √ (3/2).
  • In the case of a streamline flow, the tangent drawn at any point of the curve (path) will correspond to the flow velocity at that point.
  • The diagram below represents a curve with tangent in different directions.
  • It describes how particles in a liquid move with respect to time.
  • The pressure in point 2 is equal to the pressure in position 3.
  • Note that the length should be in meters.
  • The pressure in point 4 is the same as that in point 5, as the air pressure is relatively low compared to that of oil.
  • Pressure difference between the two pipes using readings on the manometer.
  • Use Soil = 0.85 and S Hg = 13.6 Solution.
  • Interesting points are placed on the manometer.
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