Physics, asked by Armaankhan060, 1 year ago

An ideal massless spring S can be compressed 2 metre by a force of 200 N. This spring is placed at the
bottom of the frictionless inclined plane with makes an angle 0 = 30° with the horizontal. A 20 kg mass
is released from rest at the top of the inclined plane and is brought to rest momentarily after
compressing the spring 4 metre. Through what distance does the mass slide before coming to rest- (g =
10 m/s)
(1) 2.2 m
(2) 4 m
(3) 8 m
(4) 1.9 m​

Answers

Answered by gogiya167
14

Answer:

    3) 8 meter

Explanation:

   spring costant k = 200/2 = 100 N/m

m = 20 kg

first compression length = 2 m

second compression length = 4m

Proceed as given in attachment below.

Attachments:
Answered by VivekKathayat
3

Answer:

8 m

answer is given in the attachment

Attachments:
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